Old Biboroku

Wednesday, November 3, 2010

Uncertainty in Flux and Magnitude

Filed under: Astro,Research — nomo17k @ 13:52
Tags: , ,

I keep forgetting this sort of simple algebra (aging is no fun), so here’s a note.

Define magnitude m to be related to flux f as follows:

m = -2.5 \log{\frac{f}{f_0}} \ ,

where f_0 is the zero point flux which defines the magnitude scale.  Let \Delta m be the magnitude uncertainty, which is related to the fractional uncertainty in flux, \Delta f / f.  We wish to find how m \pm \Delta m is related to \left(1 \mp \Delta f / f \right) f.  This means

\begin{array}{rcl} \pm \Delta m &=& -2.5 \log{\left[\left(1 \mp \frac{\Delta f}{f}\right)\frac{f}{f_0}\right]} + 2.5 \log{\frac{f}{f_0}} \\ &=& -2.5 \log{\left(1 \mp \frac{\Delta f}{f}\right)} \end{array} \ .

Solving for \Delta f / f we get

\pm \frac{\Delta f}{f} = 1 - 10^{\mp 0.4 \Delta m}  \ .

In summary, we have the following relationships:

\boxed{ \pm \Delta m = -2.5 \log{\left(1 \mp \frac{\Delta f}{f}\right)} \;\;\; \text{or} \;\;\; \pm \frac{\Delta f}{f} = 1 - 10^{\mp 0.4 \Delta m}  \ . }

When \Delta m \ll 1 or \Delta f / f \ll 1, we may expand the log function about 1 and retain only the first order term:

\begin{array}{rcl} \log{x} &=& \frac{x - 1}{\ln{10}} - \frac{(x - 1)^2}{\ln{10^2}} + \frac{(x - 1)^3}{\ln{10^3}} - ... \\ &\approx& \frac{x - 1}{\ln{10}} \end{array}

for x \simeq 1. In this limit we can write \Delta m \approx (2.5 / \ln{10}) \Delta f / f \approx 1.085736 \Delta f / f. Hence

\boxed{ \Delta m \approx 1.085736 \frac{\Delta f}{f} \;\;\; \text{for} \;\;\; \Delta m \;\text{or}\; \Delta f / f \ll 1  \ .}

This is why an uncertainty in magnitude, when small, is often an adequate approximation to the fractional uncertainty in flux.

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